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Experiment 13.2ab, the reaction between iron(III) ions and iodide ions,p368.

1.     Take 2 test-tubes 0.1M Fe3+ and 2 test-tubes 0.1M KI.

2.     Make 2 test-tube mixtures of about 2 cm 0.1M Fe3+ add 2cm3 0.1M KI.

       Changes occurring         .

3.     Add starch and Khexacyanoferrate(II) to each separate mixtures.

Added

Fe3+

0.1M KI

mixture

starch

Khexacyanoferrate

4.     Add Khexacyanoferrate to Fe2+ (should go blue).

Equation:2Fe3+(aq)+2I-(aq)-->2Fe2+(aq)+I2(aq)

To measure electrode potentials of Fe3+-->Fe2+

1.     Use Cu cell as a reference and set things up as previous example w.r.t. Cu

2.     Use beaker filled with Fe3+/Fe2+ equilibrium and platinum electrode as a electrolyte (p.369)

3.     Measure E.m.f.=                       .

4.     Now use 2I-(aq)/I2(aq) equilibrium instead of Fe3+/Fe2+ equilibrium. E.m.f.=              .

5.     Deduce the Pt|2I-(aq),I2(aq) ¦ ¦ Fe3+,Fe2+ | Pt.

6.     Measure Pt|2I-(aq),I2(aq) ¦ ¦ Fe3+,Fe2+ | Pt experimentally (need a 2nd Pt electrode)

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